Relaciona ambas columnas, para cada uno de los ejercicios se requiere que anexes los procedimientos correspondientes y sus representaciones graficas. a) Un rombo con una d = 30 y uno de sus lados = 17, encuentre el área. ( ) b = 8 cm h = 6 cm b) Halla el área de un rectángulo si su base mide 5 cm y su diagonal mide 12 cm. ( ) A = 173.2 cm2 c) La base de un paralelogramo se representa por (x + 3) y la altura (x + 1), si su área es de 48 cm2 . Calcula la base y altura. ( ) b = 36 cm h = 40 cm d) Encuentra el área de un triángulo equilátero, cuyo perímetro es de 60 cm. ( ) h = 2.8 m e) Determina la base y la altura de un paralelogramo si están a razón de 4:5 y su área es de 1280 m2 . ( ) A = 54. 55 cm f) Halla la altura de un trapecio, si sus bases miden 13 y 17 respectivamente y su área es de 42 m2 . ( ) A = 136 u2

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step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

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step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.