One number is 28 less than another number. If the sum of the two numbers is 92, find the two numbers.

The two numbers are 32 and 60.

Step-by-step explanation:

We can create two simultaneous equations to solve this problem using the information given in the question.

Let number 1 = x

Let number 1 = y

x = y - 28 -> ( 1 )

x + y = 92 -> ( 2 )

We can solve simultaneous equations using substitution or elimination. For this question, we will use substitution as it is the easier option.

Substitute ( 1 ) into ( 2 ):

x + y = 92 -> ( 2 )

( y - 28 ) + y = 92

2y - 28 = 92

2y = 120

y = 120 / 2

y = 60 -> ( 3 )

Substitute ( 3 ) into ( 1 ):

x = y - 28 -> ( 1 )

x = ( 60 ) - 28

x = 32

Therefore:

x = 32 , y = 60

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

t= 1/3.

hope this .

step-by-step explanation: