Write the equation of the line through the given point. Use slope-intercept form. 3
(-4,6); perpendicular to y = -
2x+3
Write an equation for the line in slope-intercept form.
(Simplify your answer. Use integers or fractions for any numbers in the equation)

2y=x+16

Step-by-step explanation:

condition for a perpendicular line to the previous line is that the gradient M1=-1/M2. looking at the question above the equation of the line given y=-2x+3 that is the first M1=-2. so to get the gradient M2 of the line perpendicular, then M2=-1/-2=1/2. so M2=1/2. so the equation of the new line is y=1/2x+C. so we can find C. since the line passes through (-4,6). when x=-4, y=6, 6=1/2(-4)+C..C=6+2=8. so the equation of the new line y=1/2x+8 we can multiply via 2. so we have 2y=x+16

the equation is 2y=x+16

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50