A customer wants to put in a concrete driveway that is 10" thick. How much concrete would it take to pour a driveway that measures 18' by 42'? Express your answer in cubic yards.

22.59 yd^3

Step-by-step explanation:

First the volume of a cuboid whose measurements are:

L = length, W = width and T = thiknes is:

V = L*W*T.

We want to calculate the volume of a shape that is:

10'' thick, 18' wide and 42' long.

This notation is:

(') = feet

('') = inches

The first step is to write our 3 numbers in the same units, then we can use that:

1 inch = 0.083 ft.

Then 10 inches are equal to:

10'' = 10*(0.083 ft) = 0.83 ft = 0.83'

Then the volume of concrete needed will be:

V = 0.83ft*18ft*42ft = 627.48 ft^3

But we want this expressed in yd^3

1ft = 0.33 yd

then

1ft^3 = (0.33 yd)^3 = 0.036 yd^3

then 627.48 ft^3 can be written as:

627.48 ft^3 = 627.48*( 0.036 yd^3) = 22.59 yd^3

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

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