A small town's raffle has 85 entries and 3 gift baskets that three different people could win. What is the probability of winning a gift basket if you have 1 of the entries? [1 point]

3 / 85

Step-by-step explanation:

Given the following :

Number of gift basket = 3

Nunber of entries = 85

Probability of winning a gift basket if you have one of the entries :

With one entry, one has a chance of winning one of 3 gift baskets

Hence, the required outcome of one entry = 3

Total possible outcomes = number of entries = 85

P(winning a gift basket with one entry) :

Required outcome / Total possible outcomes

= 3 / 85

Also, it could be calculated thus ;

Probability of one entry from a total of 85;

= 1/ 85.

And one entry has a Chance of winning one of 3 different gift baskets

Hence (1/85 × 3) = 3/85

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

b.   e = 7.5h

hope this , lovely!