A seagull is floating on the surface of the ocean when it takes off and flies upward at a rate of 4 ft per second. After 19 seconds, how far away from the surface of the water will the seagull be?

d = 76 m

Step-by-step explanation:

It is given that, the speed of 4 ft per second when it takes off and flies upward

We need to find how far away from the surface of the water will the seagull be after 9 seconds.

Speed is distance over time.

So,

Distance, d = vt

d=4 ft/s × 19 s

d=76 meters

So, the seagull will be at a distance of 76 m from the surface of water.

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

50-38=12

step-by-step explanation: