Find the slope given the following points: (12,-2) and (4,-6)

slope=1/2 or

y=1/2x-8

Step-by-step explanation:

use the y1-y2/x2-x1 method and y=mx+b method

plug in the -2 and -6 into the y's value

then plug in 12 and 4 into the x's value

-2+6=4

12-4=8

4/8 that can reduce to 1/2

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you can plug it into the y=mx+b method

plug in 12 for x

-2 for y

and 1/2 for m

-2=1/2(12)+b

1/2 *12=6

-2=6+b

substract 6 on both sides

-8=b and ur b is ur y-intercept

y=1/2x-8

hope this helps

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."