A domain consists of the values 1, 2, 3, and 2. A range consists of the values 5, 10, 15, and 20. The 1 in the domain corresponds to the 5 in the range, the first 2 in the domain corresponds to the 10 in the range, the 3 in the domain corresponds to the 15 in the range, and the second 2 in the domain corresponds to the 20 in the range. Does this relation represent a function? Explain.(1 point) It does not represent a function. The domain value of 2 corresponds to two values within the range.

It does not represent a function. Each value in the domain corresponds to exactly one value in the range.

It does represent a function. Each value in the domain corresponds to exactly one value in the range.

It does represent a function. The domain value of 2 corresponds to two values within the range.

It does not represent a function. The domain value of 2 corresponds to two values within the range.

Step-by-step explanation:

Given the function:

Domain : Range

1 => 5

2 => 10

3 => 15

2 => 20

For a relation to be considered a function, every domain value should have exactly 1 range value assigned to it or mapped to it.

In order words, a domain value should not have different range values.

In the relation given, domain value of 2, has more than 1 range value, 10 and 20, assigned to it. It does not have exactly 1 range value.

Therefore, the relation does not represent a function because the domain value of 2 corresponds to two values (10 and 20), within the range.

(x+3)(x+7)

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.