There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each. There are also 4 different meats. She buys One-half of a pound of each. How much total meat and cheese did Yasuko buy at the deli? One-fourth pounds 2 and one-fourth pounds 4 and one-fourth pounds 4 and one-half pounds

Question :

There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each. There are also 4 different meats. She buys One-half of a pound of each. How much total meat and cheese did Yasuko buy at the deli? a) One-fourth pounds

b) 2 and one-fourth pounds

c) 4 and one-fourth pounds

d) 4 and one-half pounds

c) 4 and one-fourth pounds

Step-by-step explanation:

From the question:

There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each.

Total pounds of cheese = 3 × (3/4)

= 9/4 pounds of cheese

There are also 4 different meats. She buys One-half of a pound of each.

Total pounds of meats she bought = 4 × (1/2)

= 4/2 pounds of meat

The total pounds of total meat and cheese did Yasuko bought at the deli =

= 9/4 pounds of cheese + 4/2 pounds of meat

L.C.M = 4

= 9 × 1 + 4 × 2/4

= 9 + 8/4

= 17/4

= 4 1/4 pounds

In words is 4 and one-fourth pounds

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant