A researcher needs 60 L of 50% concentrate solution for a certain experiment, but she has only 30% solution and 70% solution. How many liters of the 30% and the 70% solutions should she mix to get what she needs?

30 liters of 30% solution and 30 liters of 70% of solution should be mixed by the researcher to get 60 liters of 50% solution.

Step-by-step explanation:

Let 'x' liters of 30% solution and 'y' liters of 70% solution are added together to get the required 60 liters of 50% of the solution.

According to the question, 30% solution and 70% solution are mixed and so, we get

Also, sum of the final solution should be 60 liters only so, we get

Solving equations (1) and (2), we get

Hence, we can say that 30 liters of 30% solution and 30 liters of 70% of solution should be mixed by the researcher to get 60 liters of 50% solution.

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step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?