A basketball player makes 60% of his free throws. We set him on the line of free-throw and informed him to shoot free throws until he misses. Let the random variable X be the number of free throws taken by the player until he misses. Assuming that his shots are independent, find the probability that he will miss the shot on his 6th throw. Show work detail please a) 0.04666
b) 0.03110
c) 0.01866
d) 0.00614

B. 0.03110

Step-by-step explanation:

Given

Probability of Hit = 60%

Required

Determine the probability that he misses at 6th throw

Represent Probability of Hit with P

Convert to decimal

Next; Determine the Probability of Miss (q)

Opposite probabilities add up to 1;

So,

Substitute 0.6 for p

Next,is to determine the required probability;

Since, he's expected to miss the 6th throw, the probability is:

Hence;

Option B answers the question

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .