For which values of the parameter B the following system admits a unique solution [ 1 b 1-b 2 2 0 2–2B 4 0] [x y z] = [1 2 0]

β ≠ ±1

Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,

det ≠ 0

Determinant of a 3x3 matrix is calculated by:

det

β ≠ ±1

For the system to have only one solution, β ≠ 1 or β ≠ -1.

where is the gragh

step-by-step explanation:

4163 is for ll thw skates