Steven has one bag that contains three table tennis balls numbered 1, 2, and 3. He also has a second bag that contains four table tennis balls lettered A, B, C, and D. Suppose Steven combined the table tennis balls into one large bag instead of two individual bags. What would be the P(1, B) without replacement?

P(1, B) = 1/12

Step-by-step explanation:

if given one group of 3 objects, in this case tennis balls labeled 1, 2, and 3. And another group of 4 objects, labeled a, b, c, and d. the combined probability would be 1/3 * 1/4 = 1/12. This is because there is a 1/3 chance of picking one particular object from a set of 3 total objects, and a 1/4 chance of picking one particular object from a set of 4 total objects.

1e+27

step-by-step explanation:

y=1/4x-4

step-by-step explanation: