Find all values of c such that f is continuous on (-[infinity], [infinity]). f(x) = { 3 - x^2 x less than or equal to c x, x > ca. c = -1 + squareroot 13/2, -1 - squareroot 13/2.b. c = 0. c. c = -1 = squareroot 13/2.d. c = 2.e. c = -1 + squareroot 13/2, 1 - squareroot 13/2.

a) and

Step-by-step explanation:

The idea for the solution of this equation is to find the value of c where both parts of the piecewise-defined function are the same. So we need to take the parts of the function and set them equal to each other, so we get:

and then solve for x. We move everything to one side of the equation so we get:

and we use the quadratic formula:

and we substitute:

and solve

so our two answers are:

a) and

22 and 22

step-by-step explanation:

10 plus 12 equals 22.

12 plus 10 also equals 22 because regardless of what order they're in, they're gonna equal the same thing.

answer: you need the equation in the question so i can answer it

step-by-step explanation: