EFGH is a rhombus. Rhombus E F G H is shown. Diagonals are drawn from point E to point G and from point F to point H. All sides are congruent. Given EG = 16 and FH = 12, what is the length of one side of the rhombus? 6 units 8 units 10 units 14 units

10 units

Step-by-step explanation:

The diagnonals of a rhombus meet at right angle to their selves and bisect each other.

So one quarter will form a right angle triangle of base 6 and height 8.

Let The length of one side of the rhombus be x

X²= 8²+6²

X²= 64+36

X²= 100

X= √100

X= 10 units

a and c

step-by-step explanation:

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d