There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. Find the smallest integer in the sequence.

4

Step-by-step explanation:

Let the consecutive integers be x, x+1 and x+2.

There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. This means that:

2(x + x+2) = 2(x+2) + 8

2(2x + 2) = 2x + 4 + 8

4x + 4 = 2x + 12

Collect like terms

4x - 2x = 12 - 4

2x = 8

x = 8/2

x = 4

The smallest integer in the sequence is 4

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %