Find two numbers with a sum of 65. Twice the smaller number is 10 more than the larger number.

Step-by-step explanation:

Let the two numbers be x and y. If the sum of the numbers is 65, then;

x+y = 65 1

Given twice the smaller number is 10 more than the larger number, this can be written as 2x = 10+y (taking x as the smallest and y as the largest)

Therefore 2x = 10+y

x = 10+y/2 2

Substitute equation 2 into 1 to have;

10+y/2 +y = 65

Find the LCM

(10+y+2y)/2 = 65

10+3y/2 = 65

cross multiply

10+3y = 130

3y = 130 -10

3y = 120

y = 120/3

y = 40

Since 2x =10+y

2x = 10+40

2x = 50

x = 50/2

x = 25

Therefore the two numbers are 40 and 25

yes the data was not prsented

step-by-step explanation:

step-by-step explanation:

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