Calculus 2 master needed; stuck on evaluating the integral please show steps I am thinking that we want to split up the tan^5, making and then but I am not sure this is correct. Can anyone help? The thing I am unsure of is that tan^3 is still odd, so would we do the same thing again and factor so we will be left with just tanx?

Step-by-step explanation:

We want to find the integral:

First, perform the substitution y = x / 2. This yields:

Hence, the integral becomes;

Next, as you had done, let's expand the tangent term but to the fourth:

Recall that:

Hence:

We can use substitution once more. This time, let u = sec(y). Hence:

Rewrite:

Therefore:

Expand:

Reverse Power Rule:

Simplify:

Back-substitute:

Back-substitute:

Therefore:

= 2 (sec (x/2) - 2sec³(x/2) +  sec⁵(x/2) ) + C

                              3                     5

Step-by-step explanation:

∫sec(x/2) tan⁵(x/2) dx

apply u substitute u = x/2

= ∫sec(u) tan⁵(u) * 2du

= 2 *  ∫sec(u) tan⁴(u) tan(u) du

= 2 *  ∫sec(u) (tan²(u))² tan(u) du

= 2 *  ∫sec(u) (-1 + sec²(u))² tan(u) du

apply u substitute v = sec(u)

= 2 * ∫(-1 + v²)² dv

expand

= 2 * ∫1 - 2v² + v⁴ dv

sum

= 2 (v - 2v³ + v⁵ )

             3      5

substitute it back

= 2 (sec (x/2) - 2sec³(x/2) +  sec⁵(x/2) )

                              3                     5

add constant to the solution.

= 2 (sec (x/2) - 2sec³(x/2) +  sec⁵(x/2) ) + C

                              3                     5

the answer to the expression is 83