During a backgammon game, Jimmy rolled two dice on the board. Find the probability that the sum obtained was greater than 8 given that the number on one die was a 6

Step-by-step explanation:

This problem bothers on probability

Given that two dice are expected to give an outcome of sum greater than 8

But in the problem statement the first die is already settled since it is showing 6 already.

Now for the second die, the possible outcomes that will add up with the first die to produce a figure greater than 8 are (3,4,5,6)  

The probability of obtaining either of these numbers is 4/6= 2/3

Having the first die settled, this means that the probability of obtaining a sum of 8 is 2/3