Select the correct answer from each drop-down menu. The regular hexagon ABCDEF rotates 240º counterclockwise about its center to form hexagon A′B′C′D′E′F′. Point C′ of the image coincides with point of the preimage. Point D′ of the image coincides with point of the preimage.

Solution:

The point C' of the image coincides with point E of the preimage and D' of the image coincide with the point F of the preimage.

Explanation:

The regular hexagon have 6 corner points ABCDEF.

The complete angle about the center  because it is a close figure as shown in given figure. It means the line from two consecutive vertices to the center of hexagon make an angle of  because 6 lines from the vertices to the center divides the center angle in 6 equal parts.

It is given that the hexagon is rotated at  counterclockwise about the center, therefore the image of vertices shifts 4 places counterclockwise.

In figure first hexagon show preimage and second hexgon shows image. From figure it is noticed that the point C' of the image coincides with point E of the preimage and D' of the image coincide with the point F of the preimage.

therefore, the point C' of the image coincides with point E of the preimage and D' of the image coincide with the point F of the preimage.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

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