The point-slope form of the equation that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x-12). what is the standard form of the equation for this line? A) x-4y=8
B) x-4y=2
C) 4x-y=8
D) 4x-y=2

A

Step-by-step explanation:

So we know that the point-slope form of the line that passes through the points (-4,-3) and (12,1) is:

And we want to convert this to standard form.

The standard form of a linear equation is:

Where A, B, and C are integers, and, traditionally, A is positive.

So, first, multiply everything by 4 to remove the negative:

Distribute the left. The right cancels:

Add 4 to both sides. The left cancels:

Subtract x from both sides:

As I mentioned previously, the coefficient of A tends to be positive. So, divide everything by -1:

Simplify:

So, our answer is A

And we're done!

i have no clue at all sorry

step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5