Mathematics, 31.08.2020 01:01 naruto63
Find the exact area of the surface obtained by rotating the curve about the x-axis. y = sin πx 3 , 0 ≤ x ≤ 3
Answers: 3
![S = \dfrac{36}{x}[ \dfrac{u}{2} \sqrt{1+u^2}+ \dfrac{1}{2} \ In (u+ \sqrt{1+u^2}) ] ^{\frac{\pi}{3}}_{0}](/tpl/images/0735/1905/0117a.png)
![S = \dfrac{36}{x}[ \dfrac{\dfrac{\pi}{3}}{2} \sqrt{1+\dfrac{\pi^2}{9}}+ \dfrac{1}{2} \ In (\dfrac{\pi}{3}+ \sqrt{1+\dfrac{\pi^2}{9}})-0 ]](/tpl/images/0735/1905/f4baa.png)
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Find the exact area of the surface obtained by rotating the curve about the x-axis. y = sin πx 3 , 0...
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