If a dozen cookies cost $18, what is the cost for 18 cookies

What i did is. First i divided the cost of a dozen. And i took of a dozen of 18 (your cookies) and was left with 6 cookies. i also was left with 9 after dividing so if you add 6+9 so your answer is 15

For 18 cookies, the cost is 27 dollars.

Step-by-step explanation:

So we are given that:

a dozen cookies cost $18

And we have to find how many 18 cookies cost. We can solve this problem by finding the ratio, or fraction of dollars per cookie or cookie per dollars.

12 cookies             6                    2

  =       =      So this means 2 cookies per 3 dollars.

18 dollars                9                   3

Now if you increase the numerator by 9 (the numerator is cookies) and you find that there are 18 cookies, then how much money is there to pay?

This can be found by increasing the denom. by 9 as well:

3  x   9  =  27

So then the cost is 27 dollars, and that is how much you have to pay.

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages