1.11 People fit comfortably in a 5 feet by 5 feet area. Use this value to estimate the size of a crowd that is 5 feet deep on BOTH sides of the street along a 5-mile section of a parade route. (4 Points)

in 5ft by 5ft = 25ft^2, there can be 1 person

A normal street is 30ft wide

Then, if we want the width such that is 5 ft deep (from both sides)

Then we should subtract two times 5 ft:

30ft - 5ft - 5ft = 20ft.

Now the length is 5 miles

and 1 mile = 5280 ft

then 5 miles = 5*( 5280 ft) = 26,400 ft.

Then the area is:

20ft by 26,400 ft. =528,800  ft^2

And we know that in 25 ft^2 we can fit one person.

How many spaces of 25ft^2 we have in the 528,800 ft^2?

this is:

N =  528,800 ft^2/25ft^2 = 21,152

This means that in the street 21,152 people can fit comfortably.

The size of the crowd is  21,152 people.

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation: