Find the equation of the line that is parallel to y = 3x - 2 and contains the points ( 2,11 )

Below

Step-by-step explanation:

Let y' = mx + b be the equation of the second line

● m is the slope

● b is the y-intercept

The lines are parallel so they have the

same slope.

● y' = 3x + b

The second line crosses the point with the coordinates (2,11)

Replace y' by 11 and x by 2 to find b

● 11 = 3×2 + b

● 11 = 6 + b

Substract 6 from both sides

● 11 - 6 = 6 + b -6

● b = 5

So

● y' = 3x + 5

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b