Your school is 4 miles east and 1 mine south of your apartment there is a park 3 miles east and 4 miles south of your apartment estimate the distance between the park and your school

The distance between of the park to the school is approximately 8.6 miles

Step-by-step explanation:

The given information are;

The location of the school from the house = 4 miles East and 1 mile South

The location of the park from the house = 3 miles East and 4 mile South

By representing the direction East (x-direction) as being in the direction of vector and the direction South (negative y-direction)  as being in the direction of vector , we have;

The location of the school from the house = 4· +

The location of the park from the house = 3· + 4·

The distance, l, between the park and the school is given by the resultant of the two vectors as follows

= 4· + 3·

= + 4·

Therefore,

The distance between of the park to the school ≈ 8.6 miles.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

b and c

step-by-step explanation: