A jar has 2 red marbles, 3 blue marbles, and 5 green marbles. Draw two marbles at random, without replacement. What is the chance that one will be red and the other blue, in any order?

1/15

Step-by-step explanation:

Total no. of balls = 2+3+5 = 10

No. of red ball =2

Probability of 1st being red = 2/10 =1/5

Probability of 2nd being blue = 3/9 =1/3

Therefore, chance that one will be red and the other blue, in any order

= 1/5×1/3 = 1/15

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this