Ok please help i might put 50 for this one

Your question has been heard loud and clear.

a)

Initial velocity , U=50km/h = 250/18 m/s

Final velocity , V = 0 (this is because the car finally comes to rest)

From 3rd equation of motion , V^2-U^2=2AS.

Now , for a car that goes 50km/h , it has been proven that miniumum brake distance is 6 metres.

so , S = 6 metres.

Using this , we can find the distance stopped by car , and then we can find time.

0-(250/18)^2=2*A*6

0= 2*A*6+(250/18)^2

0 = -12A + 192.90 ( minus sign because car is deccelerating)

So , A = 16.07 m/s^2

V^2-U^2 = 2AS

0 - 192.90 = 2* 16.07*S

So , S (distance) = 24 metres.

Now , we know time = distance / speed

so , time = 24 / 253 = 0.094 seconds

Thank you

answer: do you still need this?

answer: the first graph

step-by-step explanation: