BE || CD1. Given 2. ∠A ≅ ∠A2. Reflexive Property 3. ∠ACD ≅ ∠ABE3. Corresponding angles formed by parallel lines and a transversal are ≅. 4. ∠ADC ≅ ∠AEB4. Corresponding angles formed by parallel lines and a transversal are ≅. 5. ΔABE ∼ ΔACD5. AA Similarity Postulate 6. AC AB = AD AE 6. Definition of Similar Triangles 7. AC = AB + BC, AD = AE + ED7. ??? 8. AB + BC AB = AE + ED AE 8. Substitution 9. AB AB + BC AB = AE AE + ED AE 9. Addition 10. BC AB = ED AE 10. Subtraction Fill in the missing reason for the proof. A)Transitive Property B)Subtraction Property C)SSS Similarity Theorem D)Segment Addition Postulate

The correct option is Segment Addition Postulate

Step-by-step explanation:

The segment addition postulate states that where there are two points on a line A and C and a third point B can only be located on the line segment AB if and only if the the distances between point A and point B as well as the distance between point B and point C satisfy the equation AB + BC = AC

Therefore, given that in the figure,  the point B is in between point A and point C on segment AC then AB + BC

Similarly, AD = AE + ED.

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

this answer is !