Solve 2x2 – 6x + 10 = 0 by completing the square.

Step-by-step explanation:

2x^2-6x+10=0

2(x^2-3x)+10=0

2(x-(3/2))^2-9/4)+10=0

2(x-(3/2))^2+10-9/2=0

2(x-(3/2))^2+(20-9)/2=0

2(x-(3/2))^2+11/2=0

2(x-(3/2))^2=-11/2

square is always positive so there is no solution

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )