A student looking at global population figures remarks that between the years 1950 and 2010 the global population can be modelled by the equation 300y = 23t − 44 180 (1950 ≤ t ≤ 2010) Using algebra, calculate the year in which the population passed 6 billion

The year in which the population passed 6 billion is 2000.

Step-by-step explanation:

We are given that a student looking at global population figures remarks that between the years 1950 and 2010 the global population can be modeled by the equation 300y = 23t − 44180; where (1950 ≤ t ≤ 2010).

And we have to calculate the year in which the population passed 6 billion.

The given expression is;

Firstly, put t = 1960   {as t lies between 1950 and 2010}

 = 3 billion

But we have to cross the population by 6 billion.

Now, put t = 1999 in the expression;

 = 5.99 billion

Still, it's not passed 6 billion, so finally put t = 2000;

 = 6.1 billion

Now, the global population has crossed 6 billion.

Hence, the year in which the population passed 6 billion is 2000.

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves