What is true of all multiples of 6? A. All multiples of 6 have 2 and 3 as factors. B. All multiples of 6 have 12 as a factor. C. All multiples of 6 must end in 2, 3, or 6. D. A multiple of 6 cannot have 5 as a factor.

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38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)