Mathematics, 27.08.2020 01:01 paigeleahfarbeoy2ork
Suppose that X and Y are independent random variables from binomial experiments where n = 4 in both cases but the probability of success is p = 0.25 for X and p = 0.5 for Y . Calculate the probability of the events (a) {X = 1, Y = 2}, (b) {X + Y = 1}.
Answers: 1
![P(X=1,Y=2)=[{n\choose x}(p_{x})^{x}(1-p_{x})^{n-x}]\times [{n\choose y}(p_{y})^{y}(1-p_{y})^{n-y}]](/tpl/images/0730/6879/210eb.png)
; Independent![=[{4\choose 1}(0.25)^{1}(1-0.25)^{4-1}]\times [{4\choose 2}(0.50)^{2}(1-0.50)^{4-2}]\\\\=0.422\times 0.375\\\\=0.15825\\\\\approx 0.1583](/tpl/images/0730/6879/a0a4e.png)
![=\{[{4\choose 0}(0.25)^{0}(1-0.25)^{4-0}]\times [{4\choose 1}(0.50)^{1}(1-0.50)^{4-1}]\}\\+\{[{4\choose 1}(0.25)^{1}(1-0.25)^{4-1}]\times [{4\choose 0}(0.50)^{0}(1-0.50)^{4-0}]\}\\\\=(0.3164\times 0.25)+(0.422\times0.0625)\\\\=0.0791+0.0264\\\\=0.1055](/tpl/images/0730/6879/691aa.png)
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