MDM4U 11. Avery and Bradley work at a large electronics manufacturer that produces DVD players. The
defective rate on the assembly line has gone up to 12% and the manager wants to know the
probability that a skid of 50 DVD players will contain at least 3 defective units.
a) Help Avery use the binomial distribution P(x)=, C. pqrs to answer this question

0.9487

Step-by-step explanation:

a) The probability of having a defective product = p = 12% = 0.12

The probability of not having a defective product = q = 1 - p = 1 - 0.12 = 0.88

The number of DVD players = n = 50

X is the number of defective products.

The  probability that a skid of 50 DVD players will contain at least 3 defective units = P(X ≥ 3) = 1 - P(X ≤ 2)

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

Using binomial:

P(X = 0) =

P(X = 1) =

P(X = 2) =

P(X ≤ 2)= 0.0017 + 0.0114 + 0.0382 = 0.0513

P(X ≥ 3) = 1 - P(X ≤ 2) = 1 - 0.0513 = 0.9487 = 94.87%

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people

answer: haha (: i’ll go see what it is

step-by-step explanation: