PLEASE HELP ASAP Molly was curious if quadrilaterals ABCDABCDABCDA, B, C, D and EFGHEFGHEFGHE, F, G, H were congruent, so she tried to map one figure onto the other using transformations: Molly concluded: "It's not possible to map ABCDABCDABCDA, B, C, D onto EFGHEFGHEFGHE, F, G, H using a sequence of rigid transformations, so the quadrilaterals are not congruent." What error did Molly make in her conclusion? Choose 1 Choose 1 (Choice A) A One more transformation — a rotation — would map ABCDABCDABCDA, B, C, D onto EFGHEFGHEFGHE, F, G, H. So the quadrilaterals are congruent. (Choice B) B One more transformation — a reflection — would map ABCDABCDABCDA, B, C, D onto EFGHEFGHEFGHE, F, G, H. So the quadrilaterals are congruent. (Choice C) C There is no error. This is a correct conclusion.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

answer: b

step-by-step explanation: im sorry bro bro but thats not a eqation the human mind can answer and plus im a devil

b if for most of the graph

d if y intercept

step-by-step explanation: