7) If AB = 3x - 8 and BC = x + 12, find the value of x.

Step-by-step explanation:

The question is incomplete. Here is the complete question.

In a square ABCD, if AB = (3x-8) and BC = (x+12), find the value of x. Also, find the length of each side of the square.

Note that all sides of a square are equal. Hence AB = BC for the square ABCD.

Given AB = (3x-8) and BC = (x+12), then AB = BC

3x-8 = x+12

collect like terms;

3x-x = 12+8

2x = 20

x = 20/2

x = 10

Substitute x = 10 into any of the side. Using side AB

AB = 3x-8

AB = 3(10)-8

AB = 30-8

AB = 22

BC = x+12

BC = 10+12

BC = 22

Hence x = 10 and the length of each side is 22

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w