If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t^2. Find the average speed over the given time intervals. [1, 2]

Step-by-step explanation:

Average speed is the change in distance of a body with respect to time. This is expressed as:

Given the function of the height in metres expressed as y = 56t − 1.86t² and time interval [1,2]

t₁ = 1sec and t₂ = 2 secs

y(t₂) = 56t₂ − 1.86t₂²

y(2) = 56(2) − 1.86(2)²

y(2) = 112-7.44

y(2) = 104.56

y(t₁ ) = 56t₁  − 1.86t₁ ²

y(1) = 56(1) − 1.86(1)²

y(1) = 56-1.86

y(1) = 54.14

Substituting the derived value into the formula for finding the average speed:

Hence, the average speed over the given time intervals. [1, 2] is 50.42m/s

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

nswer: a   y-axis

step-by-step explanation: