The length of a rectangle is (t – 8) units, and its width is ('+ 11) units. Which expression can represent the area of the rectangle? A 2 - 33 - 88
B. 22 - 33 + 88
C12 + 31 - 88
D I2 +31 +88

Corrected Question:

The length of a rectangle is (t – 8) units, and its width is (t + 11) units. Which expression can represent the area of the rectangle?

t² + 3t - 88

Step-by-step explanation:

Given:

Rectangle of;

length = (t - 8) units

width = (t + 11) units

The area A of a rectangle is given by;

A  = length x width (i)

Substitute the given length and width into equation (i) as follows;

A = (t - 8) x (t + 11)    [expand the brackets]

A = t² -8t + 11t - 88

A = t² + 3t - 88

Therefore, the area is

(t² + 3t - 88) square units

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

idk

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