Riya is applying mulch to her garden. She applies it at a rate of 250{,}000\text{ cm}^3250,000 cm 3 250, comma, 000, start text, space, c, m, end text, cubed of mulch for every \text{ m}^2 m 2 start text, space, m, end text, squared of garden space. At what rate is Riya applying mulch in \dfrac{\text{m}^3}{\text{m}^2} m 2 m 3 start fraction, start text, m, end text, cubed, divided by, start text, m, end text, squared, end fraction?

Complete Question

Riya is applying to her garden. She applies it at a rate of 25, 000 cm³ of mulch for every m² of garden space. At what rate is Riya applying mulch in m³/m²

0.25m³/m²

Step-by-step explanation:

We are told the Riya sprays mulch at 250,000cm³ per m²

To find the rate at which Riya is spaying the mulch in m³/m² we would have to convert 250,00cm³/m² to m³/m²

1 cm³ = 1 × 10^-6m³

250,000 cm³ = x m³

Cross Multiply

1 cm³ × xm³ = 250,000cm³ × 1 × 10^-6 m³

X

x m³ = 250,000cm³ × 1 × 10^-6 m³/1 cm³

= 0.25m³

Therefore, the rate at which Riya is spraying the mulch = 0.25m³/m²

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step-by-step explanation: ; )

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is