B) In a box of 10 oranges, 3 are bad. If two oranges are drawn at random one after the other without replacement, find the probability that
(i)both are good
(ii)one is good and the other is bad

i

i) 7/15

ii) 7/15

Step-by-step explanation:

total: 10

good: 7

bad: 3

i) both are good

p(both good) = 7/10 * 6/9 = 42/90 = 7/15

ii) one good & one bad

p(first good & second bad) = 7/10 * 3/9 = 21/90 = 7/30

p(first bad & second good) = 3/10 * 7/9 = 21/90 = 7/30

p(one good & one bad) = 7/30 + 7/30 = 14/30 = 7/15

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

45

step-by-step explanation: