Prove that \P(A) \cup \P(B) \subseteq \P(A \cup B) and find a counter-example to show that we don't always have equality

P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when ∈ P ( A U B )

Step-by-step explanation:

To  Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well

there would be 365 different 4 digit numbers

step-by-step explanation:

i belive that it is 365 because i asked google

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day