A ball is thrown straight up in the air such that its velocity after t seconds is given by v (t) = -32t + 128 feet per seconds. When does it reach the maximum height from ground?
1 second
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Question 11
6 pts
With the setup of previous question, answer the following: if the ball was thrown from the terrace of
a 64 feet tall building, height of the ball after t seconds is given by h (t) = at2 + bt + c, where a=
[Select ]
ş, b= [Select]
,C=
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