Which statement describes how the graph of a function, h(x), and its inverse, h‒1(x), are related? The line y = ‒x is the perpendicular bisector of each segment connecting a point on h(x) to the corresponding point on h‒1(x). The line y = x is the perpendicular bisector of each segment connecting a point on h(x) to the corresponding point on h‒1(x). The graph of the inverse of h(x) is a reflection over the line y = 0 of the graph of h(x). The y-axis is the perpendicular bisector of each segment connecting a point on h(x) to the corresponding point on h‒1(x).

Option B.

Step-by-step explanation:

We know that, if the graph of a function is reflected across the line y=x, then we get the graph of inverse of that function.

It means, the graph of inverse function is the mirror image of graph of function across the line y=x.

If h(x) is a function and h⁻¹(x) is its inverse function, then the line y = x is the perpendicular bisector of each segment connecting a point on h(x) to the corresponding point on h⁻¹(x).  

Therefore, the correct option is B.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this