A homeowner's backyard is a rectangle with width 18 yards long and length 16 yards long. They plan to put in a square pool with side length 5 yards long in the backyard and then want to put tile in the rest of the entire backyard. How much tile do they need to buy?

Step-by-step explanation:

Given the dimension of the  homeowner's backyard to be width 18 yards long and length 16 yards long, the area of the rectangular backyard id expreesed as;

Area of rectangle = Length * Width

Area of the rectangular backyard = 18yards * 16yards

Area of the rectangular backyard = 288yards²

If they plan to put in a square pool with side length 5 yards long in the backyard, the area of the pool = 5yd*5yd = 25yd²

The remaining area that will contain the tiles = Area of the rectangular backyard -  area of the pool

The remaining area that will contain the tiles = 288yd² - 25yd² = 263yd²

Note that we cannot determine the amount of tiles they need to buy since we are not given the dimension of each tile to use. The area needed for the tiles for the rest of the backyard is therefore 263yd².

Amount of tiles needed to buy can be expressed as 263/dimension of a tile.

853.3

step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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