One airplane is located 200 km north and 50 km east of an airport. A second plane at the same altitude is located 30 km north and 100 km north and 100 km west. The distance between the planes is closest to:
A. 150 km
B. 200 km
C. 300 km
D. 350 km
E. 400 km

B. 200 km

Step-by-step explanation:

You can use the Pythagorean theorem for this question. First, you must find a and b. You can do this by finding the distance between North and South, and East and West. For this specific equation, you'd use 200 North - 30 North to get 170 miles on the y-axis. Then, you'd do 50 East + 100 West to get 150 kilometers distance on the x-axis. Now that you have 170 and 150, you can begin the equation

 170^2 +   150^2 = c^2

28900 + 22500 = c^2

                51400 = c^2

             √51400 = √c^2

                 ~226 = c

They are approximately 226 kilometers apart, and 226 is closest to 200, which is B.

While writing this, I felt like I wasn't explaining well. Please feel free to ask for clarification if you need.

35 is an outlier

step-by-step explanation:

well

44-3-3-3=35

35+4+4+4+4=51

so the ansewr would be 51 degreesat 7: 00