A pizza restaurant offers 6 toppings to choose from for their pizzas, and no toppings is considered a plain cheese pizza. How many different pizza topping combinations are possible if the maximum number of allowed toppings is 3 and toppings can't repeat

120

Step-by-step explanation:

Given : Total toppings = 6

Number of toppings needs to be selected = 3

Also if repetition of toppings is not allowed , then the number of combinations are possible = 6 x 5 x 4   [First we choose 1 out of 6 , then 1 out of remaining 5 and then 1 out of 4,then multiplying the choices for 3 toppings]

=  120

Hence, the number of different pizza topping combinations are possible if the maximum number of allowed toppings is 3 is 120 .

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

a negative exponent is translated as follows:

so, we have