5. Taking a cruise is a costly discretionary expense. In a recent year, the top five cruise lines in the world had this many passengers:
4,133,000 2,369,000 1,295,000 928,000 679,000
Round your answers to the nearest integer.
a. The computations will be easier to work if you view this problem in terms
of thousands of passengers. Represent each number in terms of thousands
of passengers.
b. What is the mean number of passengers for these five cruise lines? (Give
the full number.)
c. What is the range? (Give the full number.)
d. What is the standard deviation? (Give the full number.)

(a) X(in '000s) = 4133, 2369, 1295, 928, 679.

(b) The mean number of passengers for these five cruise lines is 1880.8.

(c) The range of the data is 3454.

(d) The standard deviation of the data is 1414.75.

Step-by-step explanation:

We are given that in a recent year, the top five  cruise lines in the world had this many passengers:

4,133,000, 2,369,000, 1,295,000, 928,000, 679,000

(a) Let X = Number of passengers in the top five  cruise lines in the world

Representing each number in terms of thousands  of passengers below;

X(in '000s) = 4133, 2369, 1295, 928, 679

(b) The mean of the data is given by the following formula;

              Mean, =

Here, n = number of observations in data = 5

So, =

          = = 1880.8

Hence, the mean number of passengers for these five cruise lines is 1880.8.

(c) The range of the data is calculated by the following formula;

             Range = Highest value - Lowest value

                         = 4133 - 679 = 3454

Hence, the range of the data is 3454.

(d) The standard deviation of the data is given by the following formula;

       Standard deviation =

                      =  

                      =  1414.75

Hence, the standard deviation of the data is 1414.75.

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12