Show that the statement is true. If DE has endpoints D(-1,8) and E(7,-2), then the midpoint M of DE lies in Quadrant I.
D. M lies in (select)
since the x-coordinate is (select)
The midpoint M is
and the y-coordinate is (select)

midpoint = (x1 + x2) / 2, (y1 + y2)/2

(-2,1)x1 = -2 and y1 = 1

(4,-1)...x2 = 4 and y2 = -1

time to sub

m = (-2 + 4) / 2 , (1 + (-1) / 2

m = (2/2), (0/2)

m = (1,0) <==

y = -x + 1(1,0)...x = 1 and y = 0

0 = -1 + 1

0 = 0 (correct)

so the midpoint  M (1,0) lies on the line since its coordinates satisfy the equation <===

Step-by-step explanation:

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)