What is the center of a circle with the equation (x - 6)2 + (y + 2)2 = 9? A)
(6,2)
B)
(6,-2)
0)
(-6, 2)
D)
(-6, -2)

B. (6,-2)

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2

The center of the circle is (h,k)

So, in this problem, h is 6 and k is -2, so the center of this circle is (6,-2).

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm