What is the center of a circle with the equation (x − 6)2 + (y + 2)2 = 9?

centre = (6, - 2 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 6)² + (y + 2)² = 9 ← is in standard form

with (h, k ) = (6, - 2 ) ← centre

what is all that apply?

1. 2

2. 11

3. 5

4. 6

5. 7

6. 5

7. -1

8. 1

step-by-step explanation: